Asked by Spencer

Magnetic resonance imaging needs a magnetic field strength of 1.5 T. The solenoid is 1.8 m long and 75 cm in diameter. It is tightly wound with a single layer of 2.50-mm-diameter superconducting wire.

What size current is needed?

Thanks in advance
Answered by bobpursley
calculate the number of turns you can make, given diameter of wire, and length of the solenoid. Then use the solenoid equation to find current.
Answered by Spencer
i did. so length of solenoid is 1.8m. diameter of wire is 2.5e-3 m. so N=1.8/pi(2.5e-3)
I=BL/mu*N
shouldnt that be right? with L being 1.8.
Answered by Spencer
got it thank you
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