A softball that weighs 0.2 kg is thrown to a catcher. The softball hits the catcher’s mitt with a force of 1.6 N. What is the softball’s acceleration?(1 point) Responses 0.125 m/s2 0.125 m/s 2 1.8 m/s2 1.8 m/s 2 8.0 m/s2 8.0 m/s 2 0.32 m/s2 0.32 m/s 2

Answer 1

To find the acceleration of the softball, we can use Newton's second law of motion, which states that \( F = m \cdot a \), where \( F \) is the force, \( m \) is the mass, and \( a \) is the acceleration. We can rearrange this equation to solve for acceleration:

\[ a = \frac{F}{m} \]

Given:

• The force \( F = 1.6 , \text{N} \)
• The mass \( m = 0.2 , \text{kg} \)

Now, we can substitute the values into the formula:

\[ a = \frac{1.6 , \text{N}}{0.2 , \text{kg}} = 8.0 , \text{m/s}^2 \]

Thus, the acceleration of the softball is \( 8.0 , \text{m/s}^2 \). The correct response is:

8.0 m/s².