A softball that weighs 0.2 kg is thrown to a catcher. The softball hits the catcher’s mitt with a force of 1.6 N. What is the softball’s acceleration?(1 point) Responses 1.8 m/s2 1.8 m/s 2 8.0 m/s2 8.0 m/s 2 0.32 m/s2 0.32 m/s 2 0.125 m/s2

Answer 1

To find the acceleration of the softball, we can use Newton's second law of motion, which states that:

\[ F = m \cdot a \]

Where:

• \( F \) is the force applied (1.6 N),
• \( m \) is the mass of the object (0.2 kg),
• \( a \) is the acceleration.

Rearranging the formula to solve for acceleration \( a \):

\[ a = \frac{F}{m} \]

Substituting the values into the equation:

\[ a = \frac{1.6 , \text{N}}{0.2 , \text{kg}} \]

\[ a = 8.0 , \text{m/s}^2 \]

So, the acceleration of the softball is 8.0 m/s².