A Softball is Thrown at an angle of 45 degrees with the horizontal. It leaves the hand 2m above the ground. Its Initial Velocity is 20 m/s . Neglecting all external resistance, how far would it travel ? The point at which it hits the ground is at the same level as the ground at the point from which it was thrown.

Answer 1

(Vo^2/g)*sin(2*45) = 40.8 meters
(since it is caught at the same level it was thrown).