h= vₒ²•sin²α/2g,
Solve for vₒ
A basketball is thrown from the ground into the air at an angle of 30 degrees to the horizontal. If this object reaches a maximum height of 5.75m, at what velocity was it thrown?
How am i suppose to do this question if no velocity is given? I need help. I have a test tomm.
2 answers
h = 5.75 m, g = 9.81 m/s2 , θ = 30 degrees , sin(30) = 0.5
h= vₒ²•sin²α/2g, vₒ= ?
vₒ = √ (h.2g)/(sin^2θ)
vₒ = √ (5.75m . 2x9.81m/s2)/(0.5^2)
= 21.24 m/s
h= vₒ²•sin²α/2g, vₒ= ?
vₒ = √ (h.2g)/(sin^2θ)
vₒ = √ (5.75m . 2x9.81m/s2)/(0.5^2)
= 21.24 m/s
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