recall that the range is given by
R = v^2/g sin2θ
So,
v^2 = 9.8*240.3/sin74° = 2449.8
v = 49.5 m/s
Now you can use that to find the other two values.
A soccer player kicked a ball at an angle of 37 to the horizontal if the range covered by the ball is 240.3m calculate
What is the initial velocity of projection?
The time of flight?
The maximum leight attained
1 answer
1 answer