Use the kinematic equation V = V0 + at defining up as positive.
Thus, t = (V-V0)/a
V0 is given as 100 m/s
At the top of the path V = 0
a = -9.81 m/s^2 (gravity)
Thus, t is about 10 seconds
A small rocket is fired directly upwards with an initial velocity of 100m/s, How many seconds will it take
to reach its maximum height?
2 answers
t=(v-vo)/a
v=100m/sx10
a=9.81m/sx2
v=100m/sx10
a=9.81m/sx2