A small painting has an area of 400 c m

2
. The length is 4 more
than 2 times the width. Find the dimensions of the painting. Solve
by completing the square. Round answers to the nearest tenth of
a centimeter.

2 answers

width --- x
length -- 2x+4

x(2x + 4) = 400
2x^2 + 4x = 400
x^2 + 2x = 200
x^2 + 2x + 1 = 200 + 1
(x+1)^2 = 201
x+1 = ± √201
x = -1± √201
x = appr 13.18 cm or a negative, which we will reject

The width is appr 13.2 and the length is appr 30.4
no u