vi= -1.3m/s
Vf=vi-g*time
g=9.8m/s^2
A small first aid kit is dropped by a rock climber who is descending steadily at 1.3 m/s. After 2.5 s, what is the velocity of the first-aid kit, and how far is the kit below the climber?
This problem seems like it should be easy, but I'm not sure which equation to use. I'd love some help!
6 answers
Ok that makes sense. But how do I come up with the distance below the climber?
d= vi*t-1/2 g t^2
I keep getting a negative answer for this...is that ok?
Yes, d is below the starting point.
It should be -26 m/s ; 31 m
4 answers