Question

A small first-aid kit is dropped by a rock climber who is descending steadily at 1.6 m/s.
(a) After 3.5 s, what is the velocity of the first-aid kit?
(b) After the 3.5 s, how far is the kit below the climber?

Answer 1

(a) v = 1.6 m/s + (3.5 s * g)

(b) d = 3.5 s [1.6 m/s + (1/2 g * 3.5 s)]

Answer 2

what is g?

Answer 3

g is the gravitational acceleration

9.81 m/s^2

Answer 4

so a is 3.5 times 9.81 then add 1.6?