Asked by Brianna

A small first-aid kit is dropped by a rock climber who is descending steadily at 1.6 m/s.
(a) After 3.5 s, what is the velocity of the first-aid kit?
(b) After the 3.5 s, how far is the kit below the climber?

Answers

Answered by Scott
(a) v = 1.6 m/s + (3.5 s * g)

(b) d = 3.5 s [1.6 m/s + (1/2 g * 3.5 s)]
Answered by Brianna
what is g?
Answered by Scott
g is the gravitational acceleration

9.81 m/s^2
Answered by Brianna
so a is 3.5 times 9.81 then add 1.6?
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions