Well I calculate for my self but I don't sure???? They give me a formula Fdrad= 1/2PxV^2xCdxA and P=FdragxV for converting that in HP = Px(1hp/550 ft lbf/sec) ok. Fdrag=1/2 (0.0019)×(587)^2×0.398×26.72
Fdrag= 3,481.12272 slugft/sec^2
P=Fdrag×V
P=2,043,418.0363
Convert to HP = P/550
3715.3073 HP. Is that correct?????
A sleigh currently runs at 203mph, but he needs it to reach 400mph with all the packages he has to deliver.
If Goldberg is delivering presents at an altitude of 5,813.6ft, with the same drag and weight of a 2019 Challenger SRT® Hellcat Redeye, how much HP would he need to reach 400 mph?
TIPS : 100% driveline efficiency
P (air density) at 5813.6 ft = .0019 slug/ft^3
A (Area of Challenger front end) = 26.72 ft^2
C(d) (Coefficient of drag) = .398
Goldberg's sleigh required speed, 400 MPH = 587 ft/sec
F(drag) = 1/2 p x v^2 x C(d)A
P = F(drag) x V
Convert to Horsepower = P ( 1HP/550 ft lbf/sec)
4 answers
If that is the answer I hop help some body!!!!!!
Well I calculate for my self but I don't sure???? They give me a formula Fdrad= 1/2PxV^2xCdxA and P=FdragxV for converting that in HP = Px(1hp/550 ft lbf/sec) ok. Fdrag=1/2 (0.0019)×(587)^2×0.398×26.72
Fdrag= 3,481.12272 slugft/sec^2
P=Fdrag×V
P=2,043,418.0363
Convert to HP = P/550
3715.3073 HP. Is that correct?????
Fdrag= 3,481.12272 slugft/sec^2
P=Fdrag×V
P=2,043,418.0363
Convert to HP = P/550
3715.3073 HP. Is that correct?????
I don't know if that is correct. I was more curious than testing anyone. I saw the question. I have a Challenger (not the Hellcat) and the whole idea seems nuts but I wanted to know. I saw another answer of 5813. Both numbers seem pretty far fetched to me. I'm not into muscle cars for the speed. Just love the designs.