1000 kg/m3 = density of water
920 kg/m3 = density of ice
BF = Woman Weight + Slab Weight
Pvg = 50 + Pvg
V = 50 kg / (1000 - 920)
V = 50 / 80
V = 0.625 m3
A slab of ice floats on a freshwater lake.
What minimum volume must the slab have for a 50.0kg woman to be able to stand on it without getting her feet wet?
1 answer
1 answer