A slab of ice floats on a freshwater lake.

What minimum volume must the slab have for a 50.0kg woman to be able to stand on it without getting her feet wet?

1 answer

1000 kg/m3 = density of water
920 kg/m3 = density of ice

BF = Woman Weight + Slab Weight
Pvg = 50 + Pvg
V = 50 kg / (1000 - 920)
V = 50 / 80
V = 0.625 m3