a slab of ice floats on a freshwater lake what is the minimum volume must the slab have for a 45kg women to be able to stand on it without getting her feet wet?

Answer 1

Weight of ice slab + weight of woman = buoyancy force

(ice density)*V*g + Mg = (water density)*V*g

[(Water density)-(Ice density)]*V = M = 45 kg

V = 45 kg/[(Water density)-(Ice density)]
= 45kg/(1000 - 917)kg/m^3 = 0.54 m^3