A skydiver falls d1 = 495 meters in t1 = 22 s before opening his parachute. After the chute opens, he falls an additional d2 = 470 meters in t2 = 56.5 s. Write an expression that describes the skydiver's average speed, v1 during the period before opening the chute in terms of the given quantities.

Expression :
v1 = ___

2 answers

d1/t1
hehexd