I am sure that you could have done this problem three times in the time you spent typing it.
v = 27 km/hr * 1000m/km * 1 hr/3600 s
Ke = (1/2) m v^2
loss of energy = m g h
Ke at top = Ke at bottom i energy lost
(1/2) m u^2 = Ke at top
a skater with a mass of 65kg,reaches the bottom of a ramp ,2.5 metres high ,going at 27km.h-1.
calculate his kinetic energy as he reaches the ramp
calculate how fast he is going by the time he reaches the top of the ramp
2 answers
Ke at top = Ke at bottom - energy lost
3 answers