It is unclear whether the barrel is rolling or sliding. If one assumes sliding down a frictionless ramp,
F=ma
where vf^2=2a*4.2 or a=vf^2/8.4
solve for f.
Now, if rolling, come back and say so, it is more complicated.
a barrel of oil at rest has a mass of 65kg it is rolled down a 1.2m ramp. Due to constant force exerted on it, the barrel reaches a velocity of 4.2 m/s upon leaving the ramp. Find the constant force on the barrel while it is on the ramp?
Help please.
3 answers
rolling down a ramp not sliding
Now if it is rolling, the filled barrel has a moment of inertia of 1/2 Mr^2
The angular velocity at the bottom must be w=Vf/r
KE at bottom=PE at top
1/2 I w^2+ 1/2 m vf^2=mgh
so solve for h.
The angular velocity at the bottom must be w=Vf/r
KE at bottom=PE at top
1/2 I w^2+ 1/2 m vf^2=mgh
so solve for h.
3 answers