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A skateboarder travels on a horizontal surface with an initial velocity of 4.4 m/s toward the south and a constant acceleration...Asked by alison
A skateboarder travels on a horizontal surface with an initial velocity of 4.4 m/s toward the south and a constant acceleration of 2.0 m/s2 toward the east. Let the x direction be eastward and the y direction be northward, and let the skateboarder be at the origin at t=0.
I am so confused
I am so confused
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Answered by
Damon
Look, this is totally two separate problems due to the fact that south and east are 90 degrees from each other so whatever happens to an east vector does not influence south motion.
East problem (x):
xi = 0
Vix = 0 (I assume)
ax = 2.0
so
vx = 0 + 2.0 t
x = 0 + 0 + (1/2)(2.0) t^2 = t^2
yi = 0
Vyi = -4.4
vy = -4.4 forever because no acceleration is given south
y = -4.4 t
East problem (x):
xi = 0
Vix = 0 (I assume)
ax = 2.0
so
vx = 0 + 2.0 t
x = 0 + 0 + (1/2)(2.0) t^2 = t^2
yi = 0
Vyi = -4.4
vy = -4.4 forever because no acceleration is given south
y = -4.4 t
Answered by
bobpursley
http://physicshelpforum.com/kinematics-dynamics/12222-x-y-components-position-velocity.html a similar problem. I did your exact problem earlier this day, but I can't find it.
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