Question

A skateboarder travels on a horizontal surface with an initial velocity of 4.4 m/s toward the south and a constant acceleration of 2.0 m/s2 toward the east. Let the x direction be eastward and the y direction be northward, and let the skateboarder be at the origin at t=0.

What is her x position at t=0.90s?
What is her y position at t=0.90s?
What is her x velocity component at t=0.90s?
What is her y velocity component at t=0.90s?
Please list steps on how to do them if possible!

Answer 1

all positions are vectors in x,y (east, North) direction.
p(t)=pxo + pyo + Vox*t +Voy*t + 1/2 (ax*t)+1/2 (ay*t)
px(t)=0+0*t+1/2 *2*t
py(t)=0+(-4.4)t
so you put in the value for time t, and you have x and y positions
velocity? Vx=ax*t=2t
Vy=-4.4t (or -y, or South direction)