A simple pendulum consists of a 3 kg point of mass hanging at the end of a 2 m long light string that is connected to a pivot point.

Question

A simple pendulum consists of a 3 kg point of mass hanging at the end of a 2 m long light string that is connected to a pivot point.
     a. Calculate the magnitude of the torque (due to gravitational force) around this pivot point when the string makes a 5 degree angle with the vertical.
     b. Repeat this calculation for an angle of 15 degrees.

Maria · Accepted Answer

T=Fd sin() 9.8=gravity T=(3)(9.8)(2)(sin(5)) T=5.1Nm T=(3)(9.8)(2)(sin(15)) T=15 Nm

drwls · Answer

The torque about the pivot point is T = M g L sin A A is the angle, M the mass and L is the string length

Kathrine · Answer

Thanks a lot, we didn't get that formula. That might be why I was having problems. :)

Anonymous · Answer

5.299

Dalya · Answer

Good

Emran · Answer

Nice

s · Answer

Why isn't it negative? Gravity would be negative in this situation if I'm not mistaken.