Ignore the mass of the string in determining the period of the pendulum.
Tension=5.39g
massperunitlengthstring=.0789/L
periodpendulum=2PI sqrt (L/g)
solve for L, given pendulum.
wavespeed= (from the law of string)
wavespeed= sqrt (Tension/(mass/length))
A simple pendulum consists of a ball of mass
5.39 kg hanging from a uniform string of mass
0.0789 g and length L. The period of oscilla-
tion for the pendulum is 2.51 s.
Determine the speed of a transverse wave
in the string when the pendulum is station-
ary and hangs vertically. The acceleration of gravity is 9.8 m/s2 .
Answer in units of m/s.
4 answers
Im still having difficulty coming up with the correct answer.
post your work, please, I will check it. Ahhh. did you work mass in kg?
i have sample homework with solution and different numbers. Mass=5.51kg Ms=0.0754g T=1.39s.
g(1.39)^2/4*pi^2=.4796
sqrt(5.51/(.000754/.4796))=59.2
answer on this problem is 586.072 m/s
g(1.39)^2/4*pi^2=.4796
sqrt(5.51/(.000754/.4796))=59.2
answer on this problem is 586.072 m/s