To find the amount of aluminum needed to refinish the side of the silo, we can calculate the surface area of the cylindrical side of the silo. The formula for the lateral surface area \( A \) of a cylinder is given by:
\[ A = 2 \pi r h \]
where:
- \( r \) is the radius,
- \( h \) is the height of the cylinder,
- \( \pi \) is a constant approximately equal to 3.14.
Given that the radius \( r \) is 4 feet and the height \( h \) is 30 feet, we can substitute these values into the formula:
\[ A = 2 \times 3.14 \times 4 \times 30 \]
First, calculate \( 2 \times 3.14 \):
\[ 2 \times 3.14 = 6.28 \]
Next, multiply by the radius and height:
\[ A = 6.28 \times 4 \times 30 \]
Calculating \( 4 \times 30 \):
\[ 4 \times 30 = 120 \]
Now multiply by \( 6.28 \):
\[ A = 6.28 \times 120 = 753.6 \]
Therefore, the amount of aluminum the farmer needs to refinish the silo is approximately \( \boxed{753.6} \) square feet.