A shot-putter puts a shot (weight = 70.1 N) that leaves his hand at distance of 1.53 m above the ground.
(a) Find the work done by the gravitation force when the shot has risen to a height of 2.18 m above the ground. Include the correct sign for work.
(b) Determine the change (PE = PEf - PE0) in the gravitational potential energy of the shot.
a. mg(delta h)= 70.1N x 9.81 x -0.65
= -446.99 J
b. mg(delta h) = 70.1N x 9.81 x 0.65
= 446.99 J
According to the system these answers are incorrect. Can you please tell me where I went wrong?
One item that is incorrect is the number of significant digits in the answer.
On the second (b), it is not clear to me where the gravitation PE change of the shot is measured. You put it at the top, I was thinking at ground level, but the problem does not state.
1 answer