b+s = 54
2s = b+6
so b = 34
A shop sells cookies in tins of two different sizes, big and small. The total number of cookies in a bit tin and a small tin is 54. The number of cookies in 2 small tins is 6 more than the number of cookies in a big tin. Find the number of cookies in a big tin.
4 answers
cookies in small tin ---- x
cookies in big tin ----- y
x+y = 54
y = 54-x
also y = 2x - 6
then
2x-6 = 54-x
3x = 60
x = 20
y = 2(20) - 6 = 36
small tin holds 20
big tin holds 36
check: is their sum = 54 ? YES
cookies in 2 small cans = 40
big can holds 36, so 2 small cans hold 6 more than a large can
All is good
cookies in big tin ----- y
x+y = 54
y = 54-x
also y = 2x - 6
then
2x-6 = 54-x
3x = 60
x = 20
y = 2(20) - 6 = 36
small tin holds 20
big tin holds 36
check: is their sum = 54 ? YES
cookies in 2 small cans = 40
big can holds 36, so 2 small cans hold 6 more than a large can
All is good
Is that your final answer?
arggghhhh,
since when is 40-6 = 36 ?????
go with dependable oobleck
since when is 40-6 = 36 ?????
go with dependable oobleck