A ship leaves port at 1:00 P.M. and sails in the direction N36°W at a rate of 25 mi/hr. Another ship leaves port at 1:30 P.M. and sails in the direction N54°E at a rate of 16 mi/hr.
(a) Approximately how far apart are the ships at 3:00 P.M.? (Round your answer to the nearest whole number.)
(b) What is the bearing, to the nearest degree, from the first ship to the second?
5 answers
Stephanie, if you would stop typing in all-caps and just put "Math" in the subject line, you'd probably receive help. Anyone who shouts at tutors and demands things, usually is not helped.
ok, sorry, would you help me then, please
Did you make a diagram?
Did you realize that the angle between their paths is 90°
How easy is that ???
First ship goes for 2 hrs at 25 mph or distance = 50 miles
2nd ship goes for 1.5 hrs at 16 mph or distance = 24 miles
a) let x be the distance between them
x^2 = 50^2 + 24^2 = 3076
x = 55.46 km
Let the angle at the left of the triangle be Ø
tanØ = 24/50
Ø = appr 25.64°
Draw in horizontals and verticals at that vertex and you should be able to find the bearing between the two ships
Did you realize that the angle between their paths is 90°
How easy is that ???
First ship goes for 2 hrs at 25 mph or distance = 50 miles
2nd ship goes for 1.5 hrs at 16 mph or distance = 24 miles
a) let x be the distance between them
x^2 = 50^2 + 24^2 = 3076
x = 55.46 km
Let the angle at the left of the triangle be Ø
tanØ = 24/50
Ø = appr 25.64°
Draw in horizontals and verticals at that vertex and you should be able to find the bearing between the two ships
ok, thanks
Help me for that question
1 answer