Asked by SK
A ship leaves its homeport and sails on a bearing of N28degrees10'E. Another ship leaves the same port at the same time and sails on a bearing of S61degrees50'E. If the first ship sails at 24.0 mph and second sails at 28mph, find the distance between the two ships after 4hrs.
Answers
Answered by
pete
40
Answered by
Henry
Unless otherwise indicated, all angles are measured CCW from the +x-axis.
d1 = 24mi/h[61.83o]*4h = 96 mi[61.83o]
d2=28mi/h[331.83o]*4h=112 mi[331.83o]
D=d2-d1 = 112mi[331.83o] - 96mi[61.83] =
98.7-52.9i - (45.3+84.6i)=53.4 - 137.5i
= 147.5mi[68.8o] S. of E.
d1 = 24mi/h[61.83o]*4h = 96 mi[61.83o]
d2=28mi/h[331.83o]*4h=112 mi[331.83o]
D=d2-d1 = 112mi[331.83o] - 96mi[61.83] =
98.7-52.9i - (45.3+84.6i)=53.4 - 137.5i
= 147.5mi[68.8o] S. of E.
Answered by
alex
i think it is 45323
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