ships travel on headings, not bearings.
The angle turned is 75°, so the distance d from port is
d^2 = 21^2 + 45^2 - 2*21*45*cos75° = 1977
so, d = 44.46 km
21 @ 32° = <21 sin32°, 21cos32°>
45 @ 287° = <-75cos17°, 75sin17°>
add the x- and y-displacements, to get the final location. Then you can calculate the bearing (back whence it started)
A ship leaves port and travels 21km on a bearing of o32 degrees and then 45km on a bearing of 287 degrees.
a. calculate its distance from the port.
b. calculate the bearing of the port from the ship
10 answers
a. d = 21[32] + 45[287].
X = 21*sin32 + 45*sin287 = -31.9km.
Y = 21*Cos32 + 45*Cos287 = 30.97km.
d = sqrt(X^2 + Y^2) = 44.46 km.
b. Tan A = X/Y
A = -45.8o = 314.2o CW from +y axis.
X = 21*sin32 + 45*sin287 = -31.9km.
Y = 21*Cos32 + 45*Cos287 = 30.97km.
d = sqrt(X^2 + Y^2) = 44.46 km.
b. Tan A = X/Y
A = -45.8o = 314.2o CW from +y axis.
a ship leave port and travel 21km on a bearing of 032 degree and then 45km on a bearing of 287 degree
a) calculate it's distance from the port. b) calculate the bearing of the port from the ship.
a) calculate it's distance from the port. b) calculate the bearing of the port from the ship.
the diagram for interpretation
Rosemary
Diagram for this question please
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Fantabulous
Please diagram
2 answers