I = 0.707*4 = 2.828A rms.
P = I^2*R = (2.828)^2 * 60 = 480 kW.
a series RLC circuit has a peak current of 4 A with a frequency of 23 kHz. if the resistance of the circuit is 60 kohm, the capacitance of the circuit is 16 uF, and the unductance of the circuit is 24 uH, determine the average power of the circuit.
1 answer