A scuba diver creates a spherical bubble with a radius of 4.0 at a depth of 30.0 where the total pressure (including atmospheric pressure) is 4.00 .
What is the radius of the bubble when it reaches the surface of the water? (Assume atmospheric pressure to be 1.00 and the temperature to be 298 .)
2 answers
the 4.0 is cm, depth is 30 m, and pressure is 4.00atm
Convert 4 cm radius to volume. volume of sphere is (4/3)*pi*r^3
Use PV = nRT to solve for n but you need temperature at the depths which isn't listed in your post.
After finding n, use PV = nRT at the new conditions and solve for volume, then convert to radius. Frankly, I don't think the problem is solvable without knowing the temperature of the water at 30 meters.
Use PV = nRT to solve for n but you need temperature at the depths which isn't listed in your post.
After finding n, use PV = nRT at the new conditions and solve for volume, then convert to radius. Frankly, I don't think the problem is solvable without knowing the temperature of the water at 30 meters.
1 answer