A scuba diver creates a spherical bubble with a radius of 4.0cm at a depth of 30.0m where the total pressure (including atmospheric pressure) is 4.00 atm.
What is the radius of the bubble when it reaches the surface of the water? (Assume atmospheric pressure to be 1.00atm and the temperature to be 298 K)
2 answers
See my response to your earlier post.
You start by calculating the volume from the radius of the bubble using the formula: V=4/3pi(r)^3 // Where R is the value of the radius. After this you would use ^3sqrt to make it into plain centimeters. Then you use the formula P1/V1 = P2/V2 and find your solution, in this case it's 6.44.