A scientist wants to make a solution of tribasic sodium phosphate, Na3PO4, for a laboratory experiment. How many grams of Na3PO4 will be needed to produce 400mL of a solution that has a concentration of Na+ ions of 1.10M ?

4 answers

How many mols Na^+ do you need? That's M x L = 1.10M x 0.400L = 0.44 mols.
Convert 0.44 mols Na^+ to mols Na3PO4. You know Na3PO4 has 3 Na ions in 1 molecule Na3PO4. Therefore 0.44 mols Na^+ x (1 mols Na3PO4/3 mols Na^+) = 0.44/3 = ?
Then g Na3PO4 = mols Na3PO4 x molar mass Na3PO4.
35.4m
35.4m is not correct
It's 24.0 g.
(0.44/3 mol)*163.94g/mol= 24.04453 g