Two masses m1= 35.0 Kg and m2= 15.0Kg are connected by a mass less string over a smooth pulley (no friction), the mass m1 being on a horizontal frictionless table. The motion of the system involves m1 moving horizontally to the right and m2 vertically downward, both with uniform acceleration "a," the string having tension "T."
Using Newton's 2nd law, write down the corresponding equations for the motion of the masses m1 and m2 relating to the tension T and acceleration a and the weight of the mass m2.
What is the relation of the weight of the mass m1 and the reaction force "R" from the surface of the table, assuming that there is a vertical motion of m1.
A satellite of mass m in a circular orbit at a height of 400Km above the earth's surface. What is the Radius of the Earth (given: 6.35 * 10^6) with respect to the center C of the Earth?
4 answers
Please post your question separately using "Post a New Question"
Do not add it as a reposnse to someone else's question
Do not add it as a reposnse to someone else's question
You do not appear to have copied the question properly. Why are you asking for the radius of the Earth when they already have told you it is 6.35*10^6 (meters)?
The actual value is 6.378*10^5 m, by the way. Don't forget to include the units (meters), which you failed to do.
If you want the radius of the satellite ORBIT, add 400 km (4*10^5 m) to that.
The actual value is 6.378*10^5 m, by the way. Don't forget to include the units (meters), which you failed to do.
If you want the radius of the satellite ORBIT, add 400 km (4*10^5 m) to that.
The actual value is 6.378*10^6 m, by the way.
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