A satellite moves at a constant speed in a circular orbit about the center of the earth at an altitude half the radius of the earth above its surface is G is the Gravitational acceleration?

Answer 1

the distance from the center of the Earth to the satellite is 1.5 times
... the distance from the center of the Earth to the surface

gravity follows an inverse-square relationship
... so g at the satellite is ... (g at the surface) / 1.5^2