Asked by dawit
A satellite moves at a constant speed in a circular orbit about the center of the earth at an altitude half the radius of the earth above its surface is G is the Gravitational acceleration?
Answers
Answered by
R_scott
the distance from the center of the Earth to the satellite is 1.5 times
... the distance from the center of the Earth to the surface
gravity follows an inverse-square relationship
... so g at the satellite is ... (g at the surface) / 1.5^2
... the distance from the center of the Earth to the surface
gravity follows an inverse-square relationship
... so g at the satellite is ... (g at the surface) / 1.5^2
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