T=2•π•R•sqrt(R/G•M)
the gravitational constant G =6.67•10^-11 N•m²/kg²,
M= 5.985•10^24 kg
T²=4π²R³/G•M
Solve for R.
V=2πR/T
A satellite is in a circular orbit about the earth (ME = 5.98 1024 kg). The period of the satellite is 3.70 104 s. What is the speed at which the satellite travels?
1 answer
1 answer