A satellite is in a circular orbit about the earth (ME = 5.98 1024 kg). The period of the satellite is 4.20 104 s. What is the speed at which the satellite travels?

1 answer

T=2•π•r/v=2•π•sqrt(r³/GM)
T²=4π²r³/GM,
r=cuberoot{GMT²/4π²}=....
v=sqrt(GM/r)=.....