Yep, you are confused. At orbit, the satellite is weightless, that leads to the conclusion the force of gravity equals the centripetal force.
mv^2/r= GMp m/r^2
note that v= 2PI r/Period.
Put that in for v, divide out the m, divide out a lot of r, and solve for G*Mp.
Now, weight=GMp 5720/(4.2E6)^2
A satellite has a mass of 5750 kg and is in a circular orbit 3.6 * 10^5 m above the surface of a planet. The period of the orbit is two hours. The radius of the planet is 4.20 * 10^6 m. What is the true weight of the satellite when it is at rest on the planet's surface?
Ok for this i know we have to use F = ma, and we also use the formula Apparent weight = mg + ma. And that F = (G m1m2)/r^2 plus ac which is v^2/r...now how do i get this started..im actually pretty confused what to do
3 answers
hold on how do i find the mass of the planet?
I suggested you solve for G*Mp
mv^2/r= GMp m/r^2
(2pi*r)^2/r= GMp /r^2
GMp= 4pi^2 r^3
If you want Mp, divide each side by G.
You are given r, the radius to the orbit.
mv^2/r= GMp m/r^2
(2pi*r)^2/r= GMp /r^2
GMp= 4pi^2 r^3
If you want Mp, divide each side by G.
You are given r, the radius to the orbit.
2 answers