It seems like you're providing a quantity of propanoic acid (CH₃-CH₂-COOH) and mentioning a sample size of \(2.80 \times 10^{23}\) molecules. If you need to calculate the mass or some other property of this sample, I can help with that!
Step 1: Calculate the number of moles
To find the number of moles of propanoic acid in your sample, use Avogadro's number, which is approximately \(6.022 \times 10^{23}\) molecules/mol.
\[ \text{Number of moles} = \frac{\text{Number of molecules}}{\text{Avogadro's number}} = \frac{2.80 \times 10^{23}}{6.022 \times 10^{23}} \approx 0.465 \text{ moles} \]
Step 2: Calculate the molar mass of propanoic acid
The molecular formula for propanoic acid (CH₃CH₂COOH) can be broken down as follows:
- Carbon (C): 3 atoms × 12.01 g/mol = 36.03 g/mol
- Hydrogen (H): 6 atoms × 1.008 g/mol = 6.048 g/mol
- Oxygen (O): 2 atoms × 16.00 g/mol = 32.00 g/mol
Adding these together gives the molar mass of propanoic acid:
\[ \text{Molar Mass} = 36.03 , \text{g/mol} + 6.048 , \text{g/mol} + 32.00 , \text{g/mol} = 74.078 , \text{g/mol} \]
Step 3: Calculate the mass of the sample
Now you can find the mass of your sample using the number of moles and the molar mass:
\[ \text{Mass} = \text{Number of moles} \times \text{Molar mass} = 0.465 , \text{moles} \times 74.078 , \text{g/mol} \approx 34.41 , \text{grams} \]
Summary
- Number of Moles: Approximately 0.465 moles
- Mass of Sample: Approximately 34.41 grams
If you need additional calculations or information, feel free to ask!