A sample of oxalic acid, H2C2O4, weighing 1.294 g is placed in a 100.0 mL volumetric flask, which is then filled to the mark with water. What is the molarity of the solution?

Answer 1

Remember the definition of molarity.
M = # mols/L.
Convert 1.294 g H2C2O4 to mols.
Then #mols/0.1 L = ??M

Answer 2

would the moles be .014?

Answer 3

Close. The # mols = 1.294/90.035 = 0.014406 which rounds to 0.01441. You have 4 significant figures in 1.294; therefore, you may have that many in the answer.