A sample of nickel is heated to 95.0°C and placed in a coffee-cup calorimeter. If the 50.0 g of water in the calorimeter is initially 22.3°C and warms to 25.4°C, what mass of nickel was heated? (The specific heat of nickel is 0.444 J/°C g and water is 4.18 J/°C g).
A. 15.4 g
B. 57.5 g
C. 2.1 g
D. 21.0 g
when I solved I got 15.35. Could you confirm my results.
3 answers
No, I don't obtain that. If you post your work I will find the error.
I tried your formula to get 470. What am I doing wrong?
m*.444*-3.1 + 50*4.18*3.1=0
-1.3764m + 647.9 =0
m = -647.9/-1.3764
m*.444*-3.1 + 50*4.18*3.1=0
-1.3764m + 647.9 =0
m = -647.9/-1.3764
Your problem is delta T. That's Tfinal-Tinitial. For the water your 3.1 is correct. Tf is 25.4 and Ti is 22.3 and dT is 3.10. But that isn't right for the Ni. Tf is 25.4 and Ti is 95.0. dT is not 3.10.