A sample of air contains 12.8 µg/m3

of beryllium
dust. How many atoms of beryllium are
present in a room with dimensions of 8 feet by
13 feet by 15.1 feet?
Answer in units of atoms

1 answer

Change feet to meters.
Find volume in m^3. length x width x height = ? m^3

12.8 ug/m^3 x ? m^3 from above = total ug Be.
Convert ug Be to g Be and convert that to mols Be. mols Be = grams Be/atomic mass Be.

Then there are 6.022E23 atoms in 1 mol Be.
Post your work if you get stuck.