a runner jops 12km north then turns and runs 16km east in three hours.a/what his displacement b/calculate his average speed c/calculate his average velocity/including the direction
3 answers
12m
if x i is east and y j is north,
displacement = 16,000 meters i + 12,000 meters j
distance (what you maybe meant to say) = 1000sqrt(16^2+12^2) = 20,000 meters = 20 km
speed = 20 km meters / 3 hours = 6.67 km/hr or 6.67 * 1000/3600 = 1.85 m/s
direction east of north = tan^-1 (16/12) = 53.1 deg east of north on compass = 36.9 deg North of east on math axes
displacement = 16,000 meters i + 12,000 meters j
distance (what you maybe meant to say) = 1000sqrt(16^2+12^2) = 20,000 meters = 20 km
speed = 20 km meters / 3 hours = 6.67 km/hr or 6.67 * 1000/3600 = 1.85 m/s
direction east of north = tan^-1 (16/12) = 53.1 deg east of north on compass = 36.9 deg North of east on math axes
sorry
displacement = 20 km
distance = 16 + 20 = 36 km
displacement = 20 km
distance = 16 + 20 = 36 km
14 answers