A runner is jogging in a straight line at a
steady vr= 3.1 km/hr. When the runner is
L= 6.1 km from the finish line, a bird begins
flying straight from the runner to the finish
line at vb= 18.6 km/hr (6 times as fast as
the runner). When the bird reaches the finish line, it turns around and flies directly back to
the runner.What cumulative distance does the bird
travel? Even though the bird is a dodo, assume that it occupies only one point in space
(a “zero” length bird), travels in a straight
line, and that it can turn without loss of
speed.
Answer in units of km.
My teacher tried giving me a formula and explaining but it still made no sense.
4 answers
I need help asap please
the bird flies for as long as it takes the runner to finish
(6.1 km / 3.1 km/hr) * 18.6 km/hr = ?
(6.1 km / 3.1 km/hr) * 18.6 km/hr = ?
i dont really see how that works out but thank you so much
I will try to make it clear.
The runner takes a certain time to finish. (6.1 km / 3.1 km/hr) which is distance over runner speed.
The bird is flying at 18.6 km/hr for exactly that length of time.
The runner takes a certain time to finish. (6.1 km / 3.1 km/hr) which is distance over runner speed.
The bird is flying at 18.6 km/hr for exactly that length of time.