The acceleration is a = F/m = 20 m/s^2 while the engine burns, if you assume the mass remains constant.
The horizontal component of acceleration is ax = a cos 60 = 10 m/s^2 and the vertical component is a sin 60 = 17.32 m/s^2
While burning, the equations of motion are
Y = (1/2) ay t^2 and
X = (1/2) ax t^2
Calculate the position and velocity at t = 50 s, and then use that to predict when and where the rocket comes down, using a different no-thrust equation of motion for t>50 s.
a rocket with mass 3000kg is fired from the ground at an angle of 60 degrees. the motor creates a force of 60000N for 50sec then cuts out. how do i find total horizontal distance from leaving the ground to hitting the ground again?? no air resistance
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