phase 1
a = 58.8 and t = 5
Hi = (1/2) a t^2 = 29.4*25 = 735 meters
Vi = a t = 58.8 * 5 = 294 m/s
Phase 2
a = -9.81 m/s^2
v = Vi - a t
v = 294 - 9.81 t
v = 0 at top
t = 30 seconds more
h = 735 + 294(30) -4.9 (30^2)
= 735 + 8811 - 4410
= 5136 meters
A rocket, initially at rest on the ground, accelerates straight upward from rest with constant acceleration 58.8 m/s2 . The acceleration period lasts for time 5.00 s until the fuel is exhausted. After that, the rocket is in free fall.
Max height
1 answer