A rocket, initially at rest on the ground, accelerates straight upward from rest with constant acceleration 58.8 m/s2 . The acceleration period lasts for time 5.00 s until the fuel is exhausted. After that, the rocket is in free fall.

Answer 1

Vo = a*t = 58.8 * 5 = 294 m/s. = Velocity at the beginning of free fall period.

V^2 = Vo^2 + 2g*h = 0 @ max ht.
(294)^2 - 19.6h = 0.
h = ?.

Answer 2

ho = 0.5a*t^2 = .5*58.8*5^2 = 735 m. = Ht. @ the beginning of free fall period.

ho + h = Ht. above gnd.