Vo = a*t = 3 * 60 = 180 m/s.
V^2 = Vo^2 + 2g*h.
0 = 180^2 - 19.6h, h = 1653 m. Above gnd.
h = 0.5g*t^2.
1653 = 4.9t^2, t = 18.4 s. To reach gnd.
V = Vo + g*t = 0 + 9.8*18.4 = 180 m/s.
A rocket accelerates upward at 3m/sec2 for 60 seconds when it releases a booster. How long will it take the booster to reach the ground from the highest point and what is its velocity as it is striking the ground?
I'm unsure how to find the time if time is already given. I was using the equation: t = (vy0 - vy)/a
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