A rocket accelerates from rest at 17 m/s2 for
11 s.
How far will it cover during this time?
Answer in units of m.
How do I solve this? do I multiply 17m/s2 by 11 seconds??
3 answers
d = 0.5a*t^2 = 0.5*17*11^2 =
1028.5
acceleration = 17m/s^2
take the anti derivative twice to get distance
P = 17/2t^2 + Ct + D
We know its at rest so it has no initial velocity, C = 0 and you can calculate it relative to a null position D = 0
Thus P = (17/2)t^2
plug in time of 11s
take the anti derivative twice to get distance
P = 17/2t^2 + Ct + D
We know its at rest so it has no initial velocity, C = 0 and you can calculate it relative to a null position D = 0
Thus P = (17/2)t^2
plug in time of 11s
1 answer