Use the following equation; the horizontal distance is irrelevant.
d=Vi+1/2at^2
Where
vi=0m/s ** there is no initial velocity in the y-direction.
a=g=9.8m/s^2
and
t=2s
Solve for d:
d=0+1/2(9.8m/s^2)(2s)^2
d=19.6.m=20m
A rock thrown horizontally from a bridge hits the water below 30 meters away in the horizontal direction. If
the rock was in the air for 2 seconds, how tall is the bridge?
1 answer
1 answer