Asked by NeedHelp!
A rock of a mass 0.2kg is attatched to a 0.75m long string and swung in a vertical plane. What is the slowest speed that the rock can travel and still maintain a circular path.
so, i started with the following equation: Fc= mv2/r
but where do i go from there to solve for v(what can i change Fc to? )
so, i started with the following equation: Fc= mv2/r
but where do i go from there to solve for v(what can i change Fc to? )
Answers
Answered by
bobpursley
at the top, mv^2/r=mg
or v= well you solve it.
or v= well you solve it.
Answered by
LALA
3 MI/HR
Answered by
NeedHelp!
Oh, so the Centripetal force= mg
how though?
how though?
Answered by
NeedHelp!
Oh, 'at the top'
great, thanks for your help :)
great, thanks for your help :)
Answered by
NeedHelp!
just to clairify,
you're suffesting that there is no tension when the rock is at the top of the swing?
you're suffesting that there is no tension when the rock is at the top of the swing?
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