A rock is thrown upward with a velocity of 28 meters per second from the top of a 38 meter high cliff, and it misses the cliff on the way back down. When will the rock be 7 meters from the water, below? Round your answer to two decimal places.

Gravity Formula

3 answers

from your data, if h is the height above the water
h = -4.9t^2 + 28t + 38

set h = 7
4.9t^2 - 28t - 31 = 0

use the quadratic formula to solve for t, use the positive result
6.46
6.64 goofy.