a rock is thrown upward with the velocity of 12 meters per second from the top of a 28 meter high cliff, and it misses the cliff on the way back down. when will the rock be 5 meters from ground level? Round your answer to two decimal places

Answer 1

the general equation is ... h = 1/2 g t^2 + v t + ho
... g is a downward acceleration

5 = -4.9 t^2 + 12 t + 28

use the quadratic formula to find t ... should be around 4 s